Base | Representation |
---|---|
bin | 1010011000110011010111… |
… | …0001111011010010110001 |
3 | 1111102212011111000000111001 |
4 | 2212030311301323102301 |
5 | 2444111124400223213 |
6 | 40142500340522001 |
7 | 2256104325631630 |
oct | 246146561732261 |
9 | 44385144000431 |
10 | 11421220320433 |
11 | 3703792136110 |
12 | 13456136b0301 |
13 | 64b02a1c7701 |
14 | 2b6b0bb1d517 |
15 | 14c15b0201dd |
hex | a6335c7b4b1 |
11421220320433 has 16 divisors (see below), whose sum is σ = 14261451992064. Its totient is φ = 8885896900560.
The previous prime is 11421220320421. The next prime is 11421220320457. The reversal of 11421220320433 is 33402302212411.
It is a cyclic number.
It is not a de Polignac number, because 11421220320433 - 221 = 11421218223281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11421220320413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 114577335 + ... + 114676972.
It is an arithmetic number, because the mean of its divisors is an integer number (891340749504).
Almost surely, 211421220320433 is an apocalyptic number.
It is an amenable number.
11421220320433 is a deficient number, since it is larger than the sum of its proper divisors (2840231671631).
11421220320433 is a wasteful number, since it uses less digits than its factorization.
11421220320433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 229254972.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11421220320433 its reverse (33402302212411), we get a palindrome (44823522532844).
The spelling of 11421220320433 in words is "eleven trillion, four hundred twenty-one billion, two hundred twenty million, three hundred twenty thousand, four hundred thirty-three".
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