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11421243993 = 33807081331
BaseRepresentation
bin10101010001100001…
…00101101001011001
31002110222002022100210
422220300211221121
5141342314301433
65125152521333
7553012654305
oct125060455131
932428068323
1011421243993
114930aa3725
122268b50249
131100296653
147a4c04d05
1546ca4c463
hex2a8c25a59

11421243993 has 4 divisors (see below), whose sum is σ = 15228325328. Its totient is φ = 7614162660.

The previous prime is 11421243991. The next prime is 11421244019. The reversal of 11421243993 is 39934212411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39934212411 = 313311404137.

It is not a de Polignac number, because 11421243993 - 21 = 11421243991 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11421243991) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1903540663 + ... + 1903540668.

It is an arithmetic number, because the mean of its divisors is an integer number (3807081332).

Almost surely, 211421243993 is an apocalyptic number.

It is an amenable number.

11421243993 is a deficient number, since it is larger than the sum of its proper divisors (3807081335).

11421243993 is an equidigital number, since it uses as much as digits as its factorization.

11421243993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3807081334.

The product of its digits is 46656, while the sum is 39.

The spelling of 11421243993 in words is "eleven billion, four hundred twenty-one million, two hundred forty-three thousand, nine hundred ninety-three".

Divisors: 1 3 3807081331 11421243993