11423020411433 has 4 divisors (see below), whose sum is σ = 11425532626320. Its totient is φ = 11420508196548.

The previous prime is 11423020411427. The next prime is 11423020411447. The reversal of 11423020411433 is 33411402032411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11423020411433 - 2⁸ = 11423020411177 is a prime.

It is a super-2 number, since 2×11423020411433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11423020411396 and 11423020411405.

It is not an unprimeable number, because it can be changed into a prime (11423020411483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1256100623 + ... + 1256109716.

It is an arithmetic number, because the mean of its divisors is an integer number (2856383156580).

Almost surely, 2^{11423020411433} is an apocalyptic number.

It is an amenable number.

11423020411433 is a deficient number, since it is larger than the sum of its proper divisors (2512214887).

11423020411433 is an equidigital number, since it uses as much as digits as its factorization.

11423020411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2512214886.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11423020411433 its reverse (33411402032411), we get a palindrome (44834422443844).

The spelling of 11423020411433 in words is "eleven trillion, four hundred twenty-three billion, twenty million, four hundred eleven thousand, four hundred thirty-three".