114240010433 has 4 divisors (see below), whose sum is σ = 114258643668. Its totient is φ = 114221377200.

The previous prime is 114240010429. The next prime is 114240010439. The reversal of 114240010433 is 334010042411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 78038098609 + 36201911824 = 279353^2 + 190268^2 .

It is a cyclic number.

It is not a de Polignac number, because 114240010433 - 2² = 114240010429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114240010399 and 114240010408.

It is not an unprimeable number, because it can be changed into a prime (114240010439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9307418 + ... + 9319683.

It is an arithmetic number, because the mean of its divisors is an integer number (28564660917).

Almost surely, 2^114240010433 is an apocalyptic number.

It is an amenable number.

114240010433 is a deficient number, since it is larger than the sum of its proper divisors (18633235).

114240010433 is an equidigital number, since it uses as much as digits as its factorization.

114240010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18633234.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 114240010433 its reverse (334010042411), we get a palindrome (448250052844).

The spelling of 114240010433 in words is "one hundred fourteen billion, two hundred forty million, ten thousand, four hundred thirty-three".