114241014411131 has 4 divisors (see below), whose sum is σ = 120961074082392. Its totient is φ = 107520954739872.

The previous prime is 114241014411119. The next prime is 114241014411137. The reversal of 114241014411131 is 131114410142411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114241014411131 is a prime.

It is a super-2 number, since 2×114241014411131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114241014411094 and 114241014411103.

It is not an unprimeable number, because it can be changed into a prime (114241014411137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3360029835605 + ... + 3360029835638.

It is an arithmetic number, because the mean of its divisors is an integer number (30240268520598).

Almost surely, 2^{114241014411131} is an apocalyptic number.

114241014411131 is a deficient number, since it is larger than the sum of its proper divisors (6720059671261).

114241014411131 is an equidigital number, since it uses as much as digits as its factorization.

114241014411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6720059671260.

The product of its (nonzero) digits is 1536, while the sum is 29.

Adding to 114241014411131 its reverse (131114410142411), we get a palindrome (245355424553542).

The spelling of 114241014411131 in words is "one hundred fourteen trillion, two hundred forty-one billion, fourteen million, four hundred eleven thousand, one hundred thirty-one".