Base | Representation |
---|---|
bin | 110101001100101011… |
… | …1110101110011011001 |
3 | 101220212202001211100211 |
4 | 1222121113311303121 |
5 | 3332432013012213 |
6 | 124252053131121 |
7 | 11153013433123 |
oct | 1523127656331 |
9 | 356782054324 |
10 | 114242313433 |
11 | 444a4897a76 |
12 | 1a183629aa1 |
13 | aa0839c441 |
14 | 575a7b2213 |
15 | 2e8978453d |
hex | 1a995f5cd9 |
114242313433 has 8 divisors (see below), whose sum is σ = 115230815840. Its totient is φ = 113256191520.
The previous prime is 114242313371. The next prime is 114242313457. The reversal of 114242313433 is 334313242411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114242313433 - 213 = 114242305241 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114242313395 and 114242313404.
It is not an unprimeable number, because it can be changed into a prime (114242313463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 498660 + ... + 690757.
It is an arithmetic number, because the mean of its divisors is an integer number (14403851980).
Almost surely, 2114242313433 is an apocalyptic number.
It is an amenable number.
114242313433 is a deficient number, since it is larger than the sum of its proper divisors (988502407).
114242313433 is a wasteful number, since it uses less digits than its factorization.
114242313433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1190247.
The product of its digits is 20736, while the sum is 31.
Adding to 114242313433 its reverse (334313242411), we get a palindrome (448555555844).
The spelling of 114242313433 in words is "one hundred fourteen billion, two hundred forty-two million, three hundred thirteen thousand, four hundred thirty-three".
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