114243013412041 has 4 divisors (see below), whose sum is σ = 114243049212292. Its totient is φ = 114242977611792.

The previous prime is 114243013411981. The next prime is 114243013412063. The reversal of 114243013412041 is 140214310342411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 31128867455625 + 83114145956416 = 5579325^2 + 9116696^2 .

It is a cyclic number.

It is not a de Polignac number, because 114243013412041 - 2¹⁵ = 114243013379273 is a prime.

It is a super-2 number, since 2×114243013412041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114243013411994 and 114243013412012.

It is not an unprimeable number, because it can be changed into a prime (114243013418041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12587946 + ... + 19670851.

It is an arithmetic number, because the mean of its divisors is an integer number (28560762303073).

Almost surely, 2^{114243013412041} is an apocalyptic number.

It is an amenable number.

114243013412041 is a deficient number, since it is larger than the sum of its proper divisors (35800251).

114243013412041 is an equidigital number, since it uses as much as digits as its factorization.

114243013412041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35800250.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 114243013412041 its reverse (140214310342411), we get a palindrome (254457323754452).

The spelling of 114243013412041 in words is "one hundred fourteen trillion, two hundred forty-three billion, thirteen million, four hundred twelve thousand, forty-one".