1142441404433 has 4 divisors (see below), whose sum is σ = 1305647319360. Its totient is φ = 979235489508.

The previous prime is 1142441404427. The next prime is 1142441404439. The reversal of 1142441404433 is 3344041442411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1142441404427) and next prime (1142441404439).

It is a cyclic number.

It is not a de Polignac number, because 1142441404433 - 2¹⁸ = 1142441142289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1142441404393 and 1142441404402.

It is not an unprimeable number, because it can be changed into a prime (1142441404439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81602957453 + ... + 81602957466.

It is an arithmetic number, because the mean of its divisors is an integer number (326411829840).

Almost surely, 2^{1142441404433} is an apocalyptic number.

It is an amenable number.

1142441404433 is a deficient number, since it is larger than the sum of its proper divisors (163205914927).

1142441404433 is an equidigital number, since it uses as much as digits as its factorization.

1142441404433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163205914926.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 1142441404433 its reverse (3344041442411), we get a palindrome (4486482846844).

The spelling of 1142441404433 in words is "one trillion, one hundred forty-two billion, four hundred forty-one million, four hundred four thousand, four hundred thirty-three".