114250433 has 4 divisors (see below), whose sum is σ = 124636848. Its totient is φ = 103864020.

The previous prime is 114250429. The next prime is 114250463. The reversal of 114250433 is 334052411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114250433 - 2² = 114250429 is a prime.

It is a super-2 number, since 2×114250433² = 26106322881374978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114250399 and 114250408.

It is not an unprimeable number, because it can be changed into a prime (114250463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5193191 + ... + 5193212.

It is an arithmetic number, because the mean of its divisors is an integer number (31159212).

Almost surely, 2^114250433 is an apocalyptic number.

It is an amenable number.

114250433 is a deficient number, since it is larger than the sum of its proper divisors (10386415).

114250433 is a wasteful number, since it uses less digits than its factorization.

114250433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10386414.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 114250433 is about 10688.7994180825. The cubic root of 114250433 is about 485.2355578030.

The spelling of 114250433 in words is "one hundred fourteen million, two hundred fifty thousand, four hundred thirty-three".