Base | Representation |
---|---|
bin | 11001111110100111011011… |
… | …101001110100000000010011 |
3 | 112222112120211101102202012211 |
4 | 121332213123221310000103 |
5 | 104433414404203241430 |
6 | 1042555340313332551 |
7 | 33031405234633306 |
oct | 3176473351640023 |
9 | 488476741382184 |
10 | 114254110212115 |
11 | 3344a994686225 |
12 | 10993266407157 |
13 | 4b9a168858243 |
14 | 202dcdd8d4b3d |
15 | d3202927c72a |
hex | 67e9dba74013 |
114254110212115 has 8 divisors (see below), whose sum is σ = 137108229960240. Its totient is φ = 91401089699232.
The previous prime is 114254110212029. The next prime is 114254110212133. The reversal of 114254110212115 is 511212011452411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114254110212115 - 215 = 114254110179347 is a prime.
It is a super-2 number, since 2×1142541102121152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 274580124 + ... + 274995913.
It is an arithmetic number, because the mean of its divisors is an integer number (17138528745030).
Almost surely, 2114254110212115 is an apocalyptic number.
114254110212115 is a deficient number, since it is larger than the sum of its proper divisors (22854119748125).
114254110212115 is an equidigital number, since it uses as much as digits as its factorization.
114254110212115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 549617621.
The product of its (nonzero) digits is 3200, while the sum is 31.
Adding to 114254110212115 its reverse (511212011452411), we get a palindrome (625466121664526).
The spelling of 114254110212115 in words is "one hundred fourteen trillion, two hundred fifty-four billion, one hundred ten million, two hundred twelve thousand, one hundred fifteen".
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