Base | Representation |
---|---|
bin | 11001111110101000110001… |
… | …000111011100010111111011 |
3 | 112222112201112022102220102112 |
4 | 121332220301013130113323 |
5 | 104433430323233334003 |
6 | 1043000134453322535 |
7 | 33031455615201266 |
oct | 3176506107342773 |
9 | 488481468386375 |
10 | 114255544043003 |
11 | 3345055aa81630 |
12 | 109935a663644b |
13 | 4b9a33692059c |
14 | 202ddd80d1cdd |
15 | d320b00a63d8 |
hex | 67ea311dc5fb |
114255544043003 has 16 divisors (see below), whose sum is σ = 126822098446560. Its totient is φ = 102055936588800.
The previous prime is 114255544042999. The next prime is 114255544043029. The reversal of 114255544043003 is 300340445552411.
It is not a de Polignac number, because 114255544043003 - 22 = 114255544042999 is a prime.
It is a super-2 number, since 2×1142555440430032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (114255544043083) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91021700 + ... + 92268417.
It is an arithmetic number, because the mean of its divisors is an integer number (7926381152910).
Almost surely, 2114255544043003 is an apocalyptic number.
114255544043003 is a deficient number, since it is larger than the sum of its proper divisors (12566554403557).
114255544043003 is a wasteful number, since it uses less digits than its factorization.
114255544043003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183291118.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 114255544043003 its reverse (300340445552411), we get a palindrome (414595989595414).
The spelling of 114255544043003 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred forty-four million, forty-three thousand, three".
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