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114255544043003 = 1161929183290117
BaseRepresentation
bin11001111110101000110001…
…000111011100010111111011
3112222112201112022102220102112
4121332220301013130113323
5104433430323233334003
61043000134453322535
733031455615201266
oct3176506107342773
9488481468386375
10114255544043003
113345055aa81630
12109935a663644b
134b9a33692059c
14202ddd80d1cdd
15d320b00a63d8
hex67ea311dc5fb

114255544043003 has 16 divisors (see below), whose sum is σ = 126822098446560. Its totient is φ = 102055936588800.

The previous prime is 114255544042999. The next prime is 114255544043029. The reversal of 114255544043003 is 300340445552411.

It is not a de Polignac number, because 114255544043003 - 22 = 114255544042999 is a prime.

It is a super-2 number, since 2×1142555440430032 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (114255544043083) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91021700 + ... + 92268417.

It is an arithmetic number, because the mean of its divisors is an integer number (7926381152910).

Almost surely, 2114255544043003 is an apocalyptic number.

114255544043003 is a deficient number, since it is larger than the sum of its proper divisors (12566554403557).

114255544043003 is a wasteful number, since it uses less digits than its factorization.

114255544043003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183291118.

The product of its (nonzero) digits is 576000, while the sum is 41.

Adding to 114255544043003 its reverse (300340445552411), we get a palindrome (414595989595414).

The spelling of 114255544043003 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred forty-four million, forty-three thousand, three".

Divisors: 1 11 61 671 929 10219 56669 623359 183290117 2016191287 11180697137 122987668507 170276518693 1873041705623 10386867640273 114255544043003