Base | Representation |
---|---|
bin | 11001111111010010001100… |
… | …001011001110011111000001 |
3 | 112222200222100000111111010111 |
4 | 121333102030023032133001 |
5 | 104440142420441344210 |
6 | 1043032412134231321 |
7 | 33034622040610120 |
oct | 3177221413163701 |
9 | 488628300444114 |
10 | 114300021434305 |
11 | 33468404338a63 |
12 | 109a0139ab5541 |
13 | 4ba15a44919c5 |
14 | 20322171a1ab7 |
15 | d33314bb288a |
hex | 67f48c2ce7c1 |
114300021434305 has 8 divisors (see below), whose sum is σ = 156754315109952. Its totient is φ = 78377157554928.
The previous prime is 114300021434297. The next prime is 114300021434321. The reversal of 114300021434305 is 503434120003411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 114300021434305 - 23 = 114300021434297 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1632857449027 + ... + 1632857449096.
It is an arithmetic number, because the mean of its divisors is an integer number (19594289388744).
Almost surely, 2114300021434305 is an apocalyptic number.
It is an amenable number.
114300021434305 is a deficient number, since it is larger than the sum of its proper divisors (42454293675647).
114300021434305 is an equidigital number, since it uses as much as digits as its factorization.
114300021434305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3265714898135.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 114300021434305 its reverse (503434120003411), we get a palindrome (617734141437716).
The spelling of 114300021434305 in words is "one hundred fourteen trillion, three hundred billion, twenty-one million, four hundred thirty-four thousand, three hundred five".
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