Base | Representation |
---|---|
bin | 10101010010100100… |
… | …11101101101110011 |
3 | 1002111120210110222212 |
4 | 22221102131231303 |
5 | 141402102440103 |
6 | 5130111122335 |
7 | 553151311565 |
oct | 125122355563 |
9 | 32446713885 |
10 | 11430124403 |
11 | 4936009705 |
12 | 226bb133ab |
13 | 1102085729 |
14 | 7a6077335 |
15 | 46d7037d8 |
hex | 2a949db73 |
11430124403 has 8 divisors (see below), whose sum is σ = 12155338080. Its totient is φ = 10710783360.
The previous prime is 11430124393. The next prime is 11430124427. The reversal of 11430124403 is 30442103411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11430124403 - 212 = 11430120307 is a prime.
It is a super-2 number, since 2×114301244032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11430124463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1464143 + ... + 1471928.
It is an arithmetic number, because the mean of its divisors is an integer number (1519417260).
Almost surely, 211430124403 is an apocalyptic number.
11430124403 is a deficient number, since it is larger than the sum of its proper divisors (725213677).
11430124403 is a wasteful number, since it uses less digits than its factorization.
11430124403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2936317.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 11430124403 its reverse (30442103411), we get a palindrome (41872227814).
The spelling of 11430124403 in words is "eleven billion, four hundred thirty million, one hundred twenty-four thousand, four hundred three".
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