Base | Representation |
---|---|
bin | 11001111111100100111011… |
… | …010101100000111100101011 |
3 | 112222202220021010011012020220 |
4 | 121333210323111200330223 |
5 | 104441010121320411410 |
6 | 1043045540341221123 |
7 | 33036233432656413 |
oct | 3177447325407453 |
9 | 488686233135226 |
10 | 114320140013355 |
11 | 334759987991a1 |
12 | 109a40137017a3 |
13 | 4ba345c5b6853 |
14 | 20331a5113643 |
15 | d33ae1053070 |
hex | 67f93b560f2b |
114320140013355 has 16 divisors (see below), whose sum is σ = 182912691598080. Its totient is φ = 60970585481568.
The previous prime is 114320140013329. The next prime is 114320140013363. The reversal of 114320140013355 is 553310041023411.
It is not a de Polignac number, because 114320140013355 - 212 = 114320140009259 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3550807 + ... + 15532176.
It is an arithmetic number, because the mean of its divisors is an integer number (11432043224880).
Almost surely, 2114320140013355 is an apocalyptic number.
114320140013355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114320140013355 is a deficient number, since it is larger than the sum of its proper divisors (68592551584725).
114320140013355 is a wasteful number, since it uses less digits than its factorization.
114320140013355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19482370.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 114320140013355 its reverse (553310041023411), we get a palindrome (667630181036766).
The spelling of 114320140013355 in words is "one hundred fourteen trillion, three hundred twenty billion, one hundred forty million, thirteen thousand, three hundred fifty-five".
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