1143203214131 has 4 divisors (see below), whose sum is σ = 1247130779064. Its totient is φ = 1039275649200.

The previous prime is 1143203214103. The next prime is 1143203214151. The reversal of 1143203214131 is 1314123023411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1143203214131 - 2⁶ = 1143203214067 is a prime.

It is a super-2 number, since 2×1143203214131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1143203214131.

It is not an unprimeable number, because it can be changed into a prime (1143203214151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51963782450 + ... + 51963782471.

It is an arithmetic number, because the mean of its divisors is an integer number (311782694766).

Almost surely, 2^{1143203214131} is an apocalyptic number.

1143203214131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1143203214131 is a deficient number, since it is larger than the sum of its proper divisors (103927564933).

1143203214131 is a wasteful number, since it uses less digits than its factorization.

1143203214131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103927564932.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1143203214131 its reverse (1314123023411), we get a palindrome (2457326237542).

The spelling of 1143203214131 in words is "one trillion, one hundred forty-three billion, two hundred three million, two hundred fourteen thousand, one hundred thirty-one".