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114320433 = 3211313577
BaseRepresentation
bin1101101000001…
…10010000110001
321222010002011010
412310012100301
5213231223213
615202141133
72555464503
oct664062061
9258102133
10114320433
11595926a7
12323517a9
131a8b8a36
141127bd73
15a082ac3
hex6d06431

114320433 has 16 divisors (see below), whose sum is σ = 153905216. Its totient is φ = 75479040.

The previous prime is 114320431. The next prime is 114320443. The reversal of 114320433 is 334023411.

It is not a de Polignac number, because 114320433 - 21 = 114320431 is a prime.

It is a super-2 number, since 2×1143204332 = 26138322802614978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114320431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 197841 + ... + 198417.

It is an arithmetic number, because the mean of its divisors is an integer number (9619076).

Almost surely, 2114320433 is an apocalyptic number.

It is an amenable number.

114320433 is a deficient number, since it is larger than the sum of its proper divisors (39584783).

114320433 is a wasteful number, since it uses less digits than its factorization.

114320433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1104.

The product of its (nonzero) digits is 864, while the sum is 21.

The square root of 114320433 is about 10692.0733723633. The cubic root of 114320433 is about 485.3346370904.

Adding to 114320433 its reverse (334023411), we get a palindrome (448343844).

The spelling of 114320433 in words is "one hundred fourteen million, three hundred twenty thousand, four hundred thirty-three".

Divisors: 1 3 211 313 577 633 939 1731 66043 121747 180601 198129 365241 541803 38106811 114320433