114331051412041 has 4 divisors (see below), whose sum is σ = 114821742620052. Its totient is φ = 113840360204032.

The previous prime is 114331051411931. The next prime is 114331051412069. The reversal of 114331051412041 is 140214150133411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80322373175625 + 34008678236416 = 8962275^2 + 5831696^2 .

It is a cyclic number.

It is not a de Polignac number, because 114331051412041 - 2²³ = 114331043023433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114331051411994 and 114331051412012.

It is not an unprimeable number, because it can be changed into a prime (114331051472041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245345603656 + ... + 245345604121.

It is an arithmetic number, because the mean of its divisors is an integer number (28705435655013).

Almost surely, 2^{114331051412041} is an apocalyptic number.

It is an amenable number.

114331051412041 is a deficient number, since it is larger than the sum of its proper divisors (490691208011).

114331051412041 is an equidigital number, since it uses as much as digits as its factorization.

114331051412041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 490691208010.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 114331051412041 in words is "one hundred fourteen trillion, three hundred thirty-one billion, fifty-one million, four hundred twelve thousand, forty-one".