114331100301113 has 4 divisors (see below), whose sum is σ = 114335222002320. Its totient is φ = 114326978599908.

The previous prime is 114331100301059. The next prime is 114331100301157. The reversal of 114331100301113 is 311103001133411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114331100301113 - 2¹⁰ = 114331100300089 is a prime.

It is a super-2 number, since 2×114331100301113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114331100301163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2060808995 + ... + 2060864472.

It is an arithmetic number, because the mean of its divisors is an integer number (28583805500580).

Almost surely, 2^{114331100301113} is an apocalyptic number.

It is an amenable number.

114331100301113 is a deficient number, since it is larger than the sum of its proper divisors (4121701207).

114331100301113 is an equidigital number, since it uses as much as digits as its factorization.

114331100301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4121701206.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 114331100301113 its reverse (311103001133411), we get a palindrome (425434101434524).

The spelling of 114331100301113 in words is "one hundred fourteen trillion, three hundred thirty-one billion, one hundred million, three hundred one thousand, one hundred thirteen".