Base | Representation |
---|---|
bin | 11001111111101111100000… |
… | …101001001101101001110011 |
3 | 112222210222121001021122000021 |
4 | 121333233200221031221303 |
5 | 104441201404324234220 |
6 | 1043055100105104311 |
7 | 33040115143524025 |
oct | 3177574051155163 |
9 | 488728531248007 |
10 | 114331503352435 |
11 | 3347a79a032016 |
12 | 109a6265188097 |
13 | 4ba4550887a25 |
14 | 2033962364015 |
15 | d340589634aa |
hex | 67fbe0a4da73 |
114331503352435 has 16 divisors (see below), whose sum is σ = 144419477479200. Its totient is φ = 86650802804736.
The previous prime is 114331503352399. The next prime is 114331503352519. The reversal of 114331503352435 is 534253305133411.
It is a cyclic number.
It is not a de Polignac number, because 114331503352435 - 217 = 114331503221363 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114331503352391 and 114331503352400.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16300681 + ... + 22234549.
It is an arithmetic number, because the mean of its divisors is an integer number (9026217342450).
Almost surely, 2114331503352435 is an apocalyptic number.
114331503352435 is a deficient number, since it is larger than the sum of its proper divisors (30087974126765).
114331503352435 is a wasteful number, since it uses less digits than its factorization.
114331503352435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6136710.
The product of its (nonzero) digits is 972000, while the sum is 43.
Adding to 114331503352435 its reverse (534253305133411), we get a palindrome (648584808485846).
The spelling of 114331503352435 in words is "one hundred fourteen trillion, three hundred thirty-one billion, five hundred three million, three hundred fifty-two thousand, four hundred thirty-five".
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