Base | Representation |
---|---|
bin | 10000101000110100000… |
… | …001111110000010110001 |
3 | 11001022010221001212000020 |
4 | 100220310001332002301 |
5 | 122213022030412431 |
6 | 2233123540314053 |
7 | 145413613424025 |
oct | 20506401760261 |
9 | 4038127055006 |
10 | 1143334232241 |
11 | 400981405073 |
12 | 1657043a2929 |
13 | 83a7b867306 |
14 | 3d4a2802385 |
15 | 1eb1a04d696 |
hex | 10a3407e0b1 |
1143334232241 has 16 divisors (see below), whose sum is σ = 1536924196800. Its totient is φ = 755998527680.
The previous prime is 1143334232177. The next prime is 1143334232281. The reversal of 1143334232241 is 1422324333411.
It is a cyclic number.
It is not a de Polignac number, because 1143334232241 - 26 = 1143334232177 is a prime.
It is a super-3 number, since 3×11433342322413 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (1143334232281) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1567170 + ... + 2177771.
It is an arithmetic number, because the mean of its divisors is an integer number (96057762300).
Almost surely, 21143334232241 is an apocalyptic number.
It is an amenable number.
1143334232241 is a deficient number, since it is larger than the sum of its proper divisors (393589964559).
1143334232241 is a wasteful number, since it uses less digits than its factorization.
1143334232241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3745776.
The product of its digits is 41472, while the sum is 33.
Adding to 1143334232241 its reverse (1422324333411), we get a palindrome (2565658565652).
The spelling of 1143334232241 in words is "one trillion, one hundred forty-three billion, three hundred thirty-four million, two hundred thirty-two thousand, two hundred forty-one".
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