114333522411131 has 4 divisors (see below), whose sum is σ = 114333610295064. Its totient is φ = 114333434527200.

The previous prime is 114333522411061. The next prime is 114333522411139. The reversal of 114333522411131 is 131114225333411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114333522411131 is a prime.

It is a super-2 number, since 2×114333522411131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114333522411091 and 114333522411100.

It is not an unprimeable number, because it can be changed into a prime (114333522411139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41960750 + ... + 44602371.

It is an arithmetic number, because the mean of its divisors is an integer number (28583402573766).

Almost surely, 2^{114333522411131} is an apocalyptic number.

114333522411131 is a deficient number, since it is larger than the sum of its proper divisors (87883933).

114333522411131 is an equidigital number, since it uses as much as digits as its factorization.

114333522411131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87883932.

The product of its digits is 25920, while the sum is 35.

Adding to 114333522411131 its reverse (131114225333411), we get a palindrome (245447747744542).

The spelling of 114333522411131 in words is "one hundred fourteen trillion, three hundred thirty-three billion, five hundred twenty-two million, four hundred eleven thousand, one hundred thirty-one".