114353344340113 has 4 divisors (see below), whose sum is σ = 114354889291188. Its totient is φ = 114351799389040.

The previous prime is 114353344340111. The next prime is 114353344340231. The reversal of 114353344340113 is 311043443353411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 68065024523409 + 46288319816704 = 8250153^2 + 6803552^2 .

It is a cyclic number.

It is not a de Polignac number, because 114353344340113 - 2¹ = 114353344340111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114353344340111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 772364506 + ... + 772512547.

It is an arithmetic number, because the mean of its divisors is an integer number (28588722322797).

Almost surely, 2^{114353344340113} is an apocalyptic number.

It is an amenable number.

114353344340113 is a deficient number, since it is larger than the sum of its proper divisors (1544951075).

114353344340113 is an equidigital number, since it uses as much as digits as its factorization.

114353344340113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1544951074.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 114353344340113 its reverse (311043443353411), we get a palindrome (425396787693524).

The spelling of 114353344340113 in words is "one hundred fourteen trillion, three hundred fifty-three billion, three hundred forty-four million, three hundred forty thousand, one hundred thirteen".