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114400400003 = 201769566987
BaseRepresentation
bin110101010001011001…
…0111001001010000011
3101221021202112110100222
41222202302321022003
53333243000300003
6124315501333255
711156643232661
oct1524262711203
9357252473328
10114400400003
114457605282a
121a20856722b
13aa3206cca6
1457737a3c31
152e985aec38
hex1aa2cb9283

114400400003 has 4 divisors (see below), whose sum is σ = 114401168760. Its totient is φ = 114399631248.

The previous prime is 114400399987. The next prime is 114400400033. The reversal of 114400400003 is 300004004411.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 114400400003 - 24 = 114400399987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114400400033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81725 + ... + 485262.

It is an arithmetic number, because the mean of its divisors is an integer number (28600292190).

Almost surely, 2114400400003 is an apocalyptic number.

114400400003 is a deficient number, since it is larger than the sum of its proper divisors (768757).

114400400003 is an equidigital number, since it uses as much as digits as its factorization.

114400400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 768756.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 114400400003 its reverse (300004004411), we get a palindrome (414404404414).

The spelling of 114400400003 in words is "one hundred fourteen billion, four hundred million, four hundred thousand, three".

Divisors: 1 201769 566987 114400400003