Base | Representation |
---|---|
bin | 10101010011111000… |
… | …11111111010001001 |
3 | 1002112100112022021002 |
4 | 22221330133322021 |
5 | 141412413042213 |
6 | 5131143224345 |
7 | 553344054206 |
oct | 125174377211 |
9 | 32470468232 |
10 | 11441143433 |
11 | 4941255445 |
12 | 22737480b5 |
13 | 1104443075 |
14 | 7a7704cad |
15 | 46e67d658 |
hex | 2a9f1fe89 |
11441143433 has 4 divisors (see below), whose sum is σ = 11810212608. Its totient is φ = 11072074260.
The previous prime is 11441143381. The next prime is 11441143513. The reversal of 11441143433 is 33434114411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33434114411 = 67 ⋅499016633.
It is a cyclic number.
It is not a de Polignac number, because 11441143433 - 26 = 11441143369 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11441143396 and 11441143405.
It is not an unprimeable number, because it can be changed into a prime (11441143333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184534541 + ... + 184534602.
It is an arithmetic number, because the mean of its divisors is an integer number (2952553152).
Almost surely, 211441143433 is an apocalyptic number.
It is an amenable number.
11441143433 is a deficient number, since it is larger than the sum of its proper divisors (369069175).
11441143433 is an equidigital number, since it uses as much as digits as its factorization.
11441143433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 369069174.
The product of its digits is 6912, while the sum is 29.
Adding to 11441143433 its reverse (33434114411), we get a palindrome (44875257844).
The spelling of 11441143433 in words is "eleven billion, four hundred forty-one million, one hundred forty-three thousand, four hundred thirty-three".
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