Base | Representation |
---|---|
bin | 10101010100001000… |
… | …00110001010011011 |
3 | 1002112111021111100200 |
4 | 22222010012022123 |
5 | 141413420311011 |
6 | 5131254033243 |
7 | 553400021001 |
oct | 125204061233 |
9 | 32474244320 |
10 | 11443135131 |
11 | 494239587a |
12 | 2274348823 |
13 | 110498c79c |
14 | 7a7aa2a71 |
15 | 46e923856 |
hex | 2aa10629b |
11443135131 has 12 divisors (see below), whose sum is σ = 16565147352. Its totient is φ = 7612060896.
The previous prime is 11443135063. The next prime is 11443135133. The reversal of 11443135131 is 13153134411.
11443135131 is a `hidden beast` number, since 1 + 144 + 3 + 1 + 3 + 513 + 1 = 666.
It is not a de Polignac number, because 11443135131 - 213 = 11443126939 is a prime.
It is a super-2 number, since 2×114431351312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11443135095 and 11443135104.
It is not an unprimeable number, because it can be changed into a prime (11443135133) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1386981 + ... + 1395206.
It is an arithmetic number, because the mean of its divisors is an integer number (1380428946).
Almost surely, 211443135131 is an apocalyptic number.
11443135131 is a deficient number, since it is larger than the sum of its proper divisors (5122012221).
11443135131 is a wasteful number, since it uses less digits than its factorization.
11443135131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2782650 (or 2782647 counting only the distinct ones).
The product of its digits is 2160, while the sum is 27.
Adding to 11443135131 its reverse (13153134411), we get a palindrome (24596269542).
The spelling of 11443135131 in words is "eleven billion, four hundred forty-three million, one hundred thirty-five thousand, one hundred thirty-one".
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