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11444343121 = 93711221251
BaseRepresentation
bin10101010100010001…
…01101000101010001
31002112120112212102001
422222020231011101
5141414222434441
65131335554001
7553413211561
oct125210550521
932476485361
1011444343121
114943040412
12227482b901
131104cc3583
147a7cd8da1
1546eab1731
hex2aa22d151

11444343121 has 4 divisors (see below), whose sum is σ = 11445573744. Its totient is φ = 11443112500.

The previous prime is 11444343077. The next prime is 11444343179. The reversal of 11444343121 is 12134344411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11444343121 - 217 = 11444212049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11444343121.

It is not an unprimeable number, because it can be changed into a prime (11444643121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601255 + ... + 619996.

It is an arithmetic number, because the mean of its divisors is an integer number (2861393436).

Almost surely, 211444343121 is an apocalyptic number.

It is an amenable number.

11444343121 is a deficient number, since it is larger than the sum of its proper divisors (1230623).

11444343121 is an equidigital number, since it uses as much as digits as its factorization.

11444343121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1230622.

The product of its digits is 4608, while the sum is 28.

Adding to 11444343121 its reverse (12134344411), we get a palindrome (23578687532).

The spelling of 11444343121 in words is "eleven billion, four hundred forty-four million, three hundred forty-three thousand, one hundred twenty-one".

Divisors: 1 9371 1221251 11444343121