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114490831307 = 1031111561469
BaseRepresentation
bin110101010100000101…
…1110111000111001011
3101221112001200211210112
41222220023313013023
53333434123100212
6124332451504535
711162122003046
oct1525013670713
9357461624715
10114490831307
11446120a9146
121a2328b814b
13aa47a13338
1457817c3c5d
152ea14c4422
hex1aa82f71cb

114490831307 has 4 divisors (see below), whose sum is σ = 115602392880. Its totient is φ = 113379269736.

The previous prime is 114490831303. The next prime is 114490831321. The reversal of 114490831307 is 703138094411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 703138094411 = 1016961763311.

It is a cyclic number.

It is not a de Polignac number, because 114490831307 - 22 = 114490831303 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114490831303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555780632 + ... + 555780837.

It is an arithmetic number, because the mean of its divisors is an integer number (28900598220).

Almost surely, 2114490831307 is an apocalyptic number.

114490831307 is a deficient number, since it is larger than the sum of its proper divisors (1111561573).

114490831307 is a wasteful number, since it uses less digits than its factorization.

114490831307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1111561572.

The product of its (nonzero) digits is 72576, while the sum is 41.

The spelling of 114490831307 in words is "one hundred fourteen billion, four hundred ninety million, eight hundred thirty-one thousand, three hundred seven".

Divisors: 1 103 1111561469 114490831307