Base | Representation |
---|---|
bin | 11010000010111100000000… |
… | …000100111000111010100001 |
3 | 120000120222100022020220122012 |
4 | 122002330000010320322201 |
5 | 110003301044423031223 |
6 | 1043344011550522305 |
7 | 33062020254521501 |
oct | 3202740004707241 |
9 | 500528308226565 |
10 | 114551074033313 |
11 | 33554923a51445 |
12 | 10a20922b06395 |
13 | 4bbc173646138 |
14 | 20404316d3a01 |
15 | d39b0a0ecc78 |
hex | 682f00138ea1 |
114551074033313 has 4 divisors (see below), whose sum is σ = 117215052499248. Its totient is φ = 111887095567380.
The previous prime is 114551074033303. The next prime is 114551074033339. The reversal of 114551074033313 is 313330470155411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 114551074033313 - 210 = 114551074032289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114551074033303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1331989232903 + ... + 1331989232988.
It is an arithmetic number, because the mean of its divisors is an integer number (29303763124812).
Almost surely, 2114551074033313 is an apocalyptic number.
It is an amenable number.
114551074033313 is a deficient number, since it is larger than the sum of its proper divisors (2663978465935).
114551074033313 is an equidigital number, since it uses as much as digits as its factorization.
114551074033313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2663978465934.
The product of its (nonzero) digits is 226800, while the sum is 41.
The spelling of 114551074033313 in words is "one hundred fourteen trillion, five hundred fifty-one billion, seventy-four million, thirty-three thousand, three hundred thirteen".
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