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114552202155 = 358985806893
BaseRepresentation
bin110101010101111010…
…1111110001110101011
3101221200100011210202220
41222223311332032223
53334100330432110
6124342523125123
711163465436566
oct1525365761653
9357610153686
10114552202155
1144643805a56
121a24b3737a3
13aa57650251
1457899db4dd
152ea6a98370
hex1aabd7e3ab

114552202155 has 16 divisors (see below), whose sum is σ = 185342891040. Its totient is φ = 60408051968.

The previous prime is 114552202139. The next prime is 114552202189. The reversal of 114552202155 is 551202255411.

It is a cyclic number.

It is not a de Polignac number, because 114552202155 - 24 = 114552202139 is a prime.

It is a super-3 number, since 3×1145522021553 (a number of 34 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42902112 + ... + 42904781.

It is an arithmetic number, because the mean of its divisors is an integer number (11583930690).

Almost surely, 2114552202155 is an apocalyptic number.

114552202155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

114552202155 is a deficient number, since it is larger than the sum of its proper divisors (70790688885).

114552202155 is an equidigital number, since it uses as much as digits as its factorization.

114552202155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85806990.

The product of its (nonzero) digits is 20000, while the sum is 33.

Adding to 114552202155 its reverse (551202255411), we get a palindrome (665754457566).

The spelling of 114552202155 in words is "one hundred fourteen billion, five hundred fifty-two million, two hundred two thousand, one hundred fifty-five".

Divisors: 1 3 5 15 89 267 445 1335 85806893 257420679 429034465 1287103395 7636813477 22910440431 38184067385 114552202155