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114555134552433 = 3315171211569783
BaseRepresentation
bin11010000010111111110010…
…000110100010100101110001
3120000121100211021211122201020
4122002333302012202211301
5110003332403421134213
61043345522521530053
733062223011413611
oct3202776206424561
9500540737748636
10114555134552433
1133556618010573
1210a21676943929
134bbc66c966b83
1420406d8abca41
15d39c96829923
hex682ff21a2971

114555134552433 has 8 divisors (see below), whose sum is σ = 152745025808448. Its totient is φ = 76367666499024.

The previous prime is 114555134552423. The next prime is 114555134552527. The reversal of 114555134552433 is 334255431555411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114555134552433 - 25 = 114555134552401 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (114555134552423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 605690341 + ... + 605879442.

It is an arithmetic number, because the mean of its divisors is an integer number (19093128226056).

Almost surely, 2114555134552433 is an apocalyptic number.

It is an amenable number.

114555134552433 is a deficient number, since it is larger than the sum of its proper divisors (38189891256015).

114555134552433 is a wasteful number, since it uses less digits than its factorization.

114555134552433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1211601303.

The product of its digits is 10800000, while the sum is 51.

The spelling of 114555134552433 in words is "one hundred fourteen trillion, five hundred fifty-five billion, one hundred thirty-four million, five hundred fifty-two thousand, four hundred thirty-three".

Divisors: 1 3 31517 94551 1211569783 3634709349 38185044850811 114555134552433