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11483251235 = 510750942169
BaseRepresentation
bin10101011000111010…
…01000001000100011
31002122021202121022022
422230131020020203
5142004203014420
65135245532055
7554365011401
oct125435101043
932567677268
1011483251235
114962aa5685
12228587402b
131110097121
147ad146471
154731e9c25
hex2ac748223

11483251235 has 16 divisors (see below), whose sum is σ = 13936341600. Its totient is φ = 9082649856.

The previous prime is 11483251231. The next prime is 11483251253. The reversal of 11483251235 is 53215238411.

It is a cyclic number.

It is not a de Polignac number, because 11483251235 - 22 = 11483251231 is a prime.

It is a super-2 number, since 2×114832512352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11483251195 and 11483251204.

It is not an unprimeable number, because it can be changed into a prime (11483251231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 251231 + ... + 293399.

It is an arithmetic number, because the mean of its divisors is an integer number (871021350).

Almost surely, 211483251235 is an apocalyptic number.

11483251235 is a deficient number, since it is larger than the sum of its proper divisors (2453090365).

11483251235 is a wasteful number, since it uses less digits than its factorization.

11483251235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42790.

The product of its digits is 28800, while the sum is 35.

Adding to 11483251235 its reverse (53215238411), we get a palindrome (64698489646).

The spelling of 11483251235 in words is "eleven billion, four hundred eighty-three million, two hundred fifty-one thousand, two hundred thirty-five".

Divisors: 1 5 107 509 535 2545 42169 54463 210845 272315 4512083 21464021 22560415 107320105 2296650247 11483251235