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1149355284481 = 4342972646473
BaseRepresentation
bin10000101110011010111…
…010011101100000000001
311001212200112201222221001
4100232122322131200001
5122312334423100411
62240001224332001
7146016044503135
oct20563272354001
94055615658831
101149355284481
114034911047a8
12166904914001
13844cb0c4411
143d8b43313c5
151ed6d943dc1
hex10b9ae9d801

1149355284481 has 4 divisors (see below), whose sum is σ = 1149358365252. Its totient is φ = 1149352203712.

The previous prime is 1149355284463. The next prime is 1149355284527. The reversal of 1149355284481 is 1844825539411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 647999240256 + 501356044225 = 804984^2 + 708065^2 .

It is a cyclic number.

It is not a de Polignac number, because 1149355284481 - 231 = 1147207800833 is a prime.

It is a super-2 number, since 2×11493552844812 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1149355284431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 888940 + ... + 1757533.

It is an arithmetic number, because the mean of its divisors is an integer number (287339591313).

Almost surely, 21149355284481 is an apocalyptic number.

It is an amenable number.

1149355284481 is a deficient number, since it is larger than the sum of its proper divisors (3080771).

1149355284481 is an equidigital number, since it uses as much as digits as its factorization.

1149355284481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3080770.

The product of its digits is 5529600, while the sum is 55.

The spelling of 1149355284481 in words is "one trillion, one hundred forty-nine billion, three hundred fifty-five million, two hundred eighty-four thousand, four hundred eighty-one".

Divisors: 1 434297 2646473 1149355284481