11494831235 has 4 divisors (see below), whose sum is σ = 13793797488. Its totient is φ = 9195864984.

The previous prime is 11494831213. The next prime is 11494831273. The reversal of 11494831235 is 53213849411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11494831235 - 2⁸ = 11494830979 is a prime.

It is a super-2 number, since 2×11494831235² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11494831192 and 11494831201.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1149483119 + ... + 1149483128.

It is an arithmetic number, because the mean of its divisors is an integer number (3448449372).

Almost surely, 2^11494831235 is an apocalyptic number.

11494831235 is a deficient number, since it is larger than the sum of its proper divisors (2298966253).

11494831235 is an equidigital number, since it uses as much as digits as its factorization.

11494831235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2298966252.

The product of its digits is 103680, while the sum is 41.

It can be divided in two parts, 1149 and 4831235, that added together give a palindrome (4832384).

The spelling of 11494831235 in words is "eleven billion, four hundred ninety-four million, eight hundred thirty-one thousand, two hundred thirty-five".