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1150130433 = 32316668557
BaseRepresentation
bin100010010001101…
…1001100100000001
32222011011200100110
41010203121210001
54323413133213
6310043141533
740333642644
oct10443314401
92864150313
101150130433
11540245021
122812148a9
1315438356a
14aca6ba5b
156ae895c3
hex448d9901

1150130433 has 8 divisors (see below), whose sum is σ = 1600181568. Its totient is φ = 733416464.

The previous prime is 1150130413. The next prime is 1150130437. The reversal of 1150130433 is 3340310511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1150130433 - 212 = 1150126337 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1150130437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8334210 + ... + 8334347.

It is an arithmetic number, because the mean of its divisors is an integer number (200022696).

Almost surely, 21150130433 is an apocalyptic number.

It is an amenable number.

1150130433 is a deficient number, since it is larger than the sum of its proper divisors (450051135).

1150130433 is a wasteful number, since it uses less digits than its factorization.

1150130433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16668583.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 1150130433 is about 33913.5729907658. The cubic root of 1150130433 is about 1047.7291613239.

Adding to 1150130433 its reverse (3340310511), we get a palindrome (4490440944).

The spelling of 1150130433 in words is "one billion, one hundred fifty million, one hundred thirty thousand, four hundred thirty-three".

Divisors: 1 3 23 69 16668557 50005671 383376811 1150130433