1150144033 has 4 divisors (see below), whose sum is σ = 1151169328. Its totient is φ = 1149118740.

The previous prime is 1150144007. The next prime is 1150144057. The reversal of 1150144033 is 3304410511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3304410511 = 3079 ⋅1073209.

It is a cyclic number.

It is not a de Polignac number, because 1150144033 - 2¹⁷ = 1150012961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1150143995 and 1150144013.

It is not an unprimeable number, because it can be changed into a prime (1150144433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 510963 + ... + 513208.

It is an arithmetic number, because the mean of its divisors is an integer number (287792332).

Almost surely, 2^1150144033 is an apocalyptic number.

It is an amenable number.

1150144033 is a deficient number, since it is larger than the sum of its proper divisors (1025295).

1150144033 is a wasteful number, since it uses less digits than its factorization.

1150144033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1025294.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 1150144033 is about 33913.7734998629. The cubic root of 1150144033 is about 1047.7332910180.

Adding to 1150144033 its reverse (3304410511), we get a palindrome (4454554544).

The spelling of 1150144033 in words is "one billion, one hundred fifty million, one hundred forty-four thousand, thirty-three".