Search a number
-
+
1150410441 = 3383470147
BaseRepresentation
bin100010010010001…
…1101111011001001
32222011200220110010
41010210131323021
54324001113231
6310053142133
740336220205
oct10444357311
92864626403
101150410441
11540416434
1228132a949
13154450b4b
14acb01b05
156aee2546
hex4491dec9

1150410441 has 4 divisors (see below), whose sum is σ = 1533880592. Its totient is φ = 766940292.

The previous prime is 1150410439. The next prime is 1150410463. The reversal of 1150410441 is 1440140511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1150410441 - 21 = 1150410439 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1150417441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191735071 + ... + 191735076.

It is an arithmetic number, because the mean of its divisors is an integer number (383470148).

Almost surely, 21150410441 is an apocalyptic number.

It is an amenable number.

1150410441 is a deficient number, since it is larger than the sum of its proper divisors (383470151).

1150410441 is an equidigital number, since it uses as much as digits as its factorization.

1150410441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383470150.

The product of its (nonzero) digits is 320, while the sum is 21.

The square root of 1150410441 is about 33917.7009981514. The cubic root of 1150410441 is about 1047.8141803020.

Adding to 1150410441 its reverse (1440140511), we get a palindrome (2590550952).

It can be divided in two parts, 11504 and 10441, that added together give a triangular number (21945 = T209).

The spelling of 1150410441 in words is "one billion, one hundred fifty million, four hundred ten thousand, four hundred forty-one".

Divisors: 1 3 383470147 1150410441