Base | Representation |
---|---|
bin | 1010011101101000001100… |
… | …1100001010101001111011 |
3 | 1111201210011010211000000110 |
4 | 2213122003030022221323 |
5 | 3001440421044021410 |
6 | 40244531002035403 |
7 | 2265100621446303 |
oct | 247320314125173 |
9 | 44653133730013 |
10 | 11504123423355 |
11 | 3735964840402 |
12 | 13596ab7a8b63 |
13 | 655aac9186b4 |
14 | 2bab3427a603 |
15 | 14e3ae2e2720 |
hex | a768330aa7b |
11504123423355 has 16 divisors (see below), whose sum is σ = 18406722507264. Its totient is φ = 6135490815840.
The previous prime is 11504123423347. The next prime is 11504123423389. The reversal of 11504123423355 is 55332432140511.
11504123423355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11504123423355 - 23 = 11504123423347 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 254509 + ... + 4803438.
It is an arithmetic number, because the mean of its divisors is an integer number (1150420156704).
Almost surely, 211504123423355 is an apocalyptic number.
11504123423355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11504123423355 is a deficient number, since it is larger than the sum of its proper divisors (6902599083909).
11504123423355 is a wasteful number, since it uses less digits than its factorization.
11504123423355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5209586.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 11504123423355 its reverse (55332432140511), we get a palindrome (66836555563866).
The spelling of 11504123423355 in words is "eleven trillion, five hundred four billion, one hundred twenty-three million, four hundred twenty-three thousand, three hundred fifty-five".
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