Base | Representation |
---|---|
bin | 10101011011011010… |
… | …01110110010111001 |
3 | 1002200202021110020212 |
4 | 22231231032302321 |
5 | 142030042000131 |
6 | 5141320000505 |
7 | 555041340404 |
oct | 125555166271 |
9 | 32622243225 |
10 | 11504250041 |
11 | 4973938369 |
12 | 2290900135 |
13 | 111453a05b |
14 | 7b1c50d3b |
15 | 474e96a2b |
hex | 2adb4ecb9 |
11504250041 has 4 divisors (see below), whose sum is σ = 11507725812. Its totient is φ = 11500774272.
The previous prime is 11504250031. The next prime is 11504250067. The reversal of 11504250041 is 14005240511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5167453225 + 6336796816 = 71885^2 + 79604^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11504250041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11504249989 and 11504250016.
It is not an unprimeable number, because it can be changed into a prime (11504250011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1732916 + ... + 1739541.
It is an arithmetic number, because the mean of its divisors is an integer number (2876931453).
Almost surely, 211504250041 is an apocalyptic number.
It is an amenable number.
11504250041 is a deficient number, since it is larger than the sum of its proper divisors (3475771).
11504250041 is an equidigital number, since it uses as much as digits as its factorization.
11504250041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3475770.
The product of its (nonzero) digits is 800, while the sum is 23.
Adding to 11504250041 its reverse (14005240511), we get a palindrome (25509490552).
The spelling of 11504250041 in words is "eleven billion, five hundred four million, two hundred fifty thousand, forty-one".
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