115111213131 has 4 divisors (see below), whose sum is σ = 153481617512. Its totient is φ = 76740808752.

The previous prime is 115111213117. The next prime is 115111213141. The reversal of 115111213131 is 131312111511.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 115111213131 - 2⁵ = 115111213099 is a prime.

It is a super-2 number, since 2×115111213131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115111213098 and 115111213107.

It is not an unprimeable number, because it can be changed into a prime (115111213141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19185202186 + ... + 19185202191.

It is an arithmetic number, because the mean of its divisors is an integer number (38370404378).

Almost surely, 2^115111213131 is an apocalyptic number.

115111213131 is a deficient number, since it is larger than the sum of its proper divisors (38370404381).

115111213131 is an equidigital number, since it uses as much as digits as its factorization.

115111213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38370404380.

The product of its digits is 90, while the sum is 21.

Adding to 115111213131 its reverse (131312111511), we get a palindrome (246423324642).

The spelling of 115111213131 in words is "one hundred fifteen billion, one hundred eleven million, two hundred thirteen thousand, one hundred thirty-one".