Base | Representation |
---|---|
bin | 10101011100010000… |
… | …10111101000100011 |
3 | 1002201020122212221200 |
4 | 22232020113220203 |
5 | 142033402123011 |
6 | 5142132252243 |
7 | 555155660241 |
oct | 125610275043 |
9 | 32636585850 |
10 | 11511364131 |
11 | 4977957283 |
12 | 2293171083 |
13 | 1115b5b187 |
14 | 7b2b83791 |
15 | 4758ee856 |
hex | 2ae217a23 |
11511364131 has 6 divisors (see below), whose sum is σ = 16627525980. Its totient is φ = 7674242748.
The previous prime is 11511364099. The next prime is 11511364133. The reversal of 11511364131 is 13146311511.
11511364131 is a `hidden beast` number, since 1 + 1 + 5 + 1 + 13 + 641 + 3 + 1 = 666.
It is not a de Polignac number, because 11511364131 - 25 = 11511364099 is a prime.
It is a super-2 number, since 2×115113641312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11511364095 and 11511364104.
It is not an unprimeable number, because it can be changed into a prime (11511364133) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 639520221 + ... + 639520238.
It is an arithmetic number, because the mean of its divisors is an integer number (2771254330).
Almost surely, 211511364131 is an apocalyptic number.
11511364131 is a deficient number, since it is larger than the sum of its proper divisors (5116161849).
11511364131 is a wasteful number, since it uses less digits than its factorization.
11511364131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1279040465 (or 1279040462 counting only the distinct ones).
The product of its digits is 1080, while the sum is 27.
Adding to 11511364131 its reverse (13146311511), we get a palindrome (24657675642).
The spelling of 11511364131 in words is "eleven billion, five hundred eleven million, three hundred sixty-four thousand, one hundred thirty-one".
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