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115114544241 = 338371514747
BaseRepresentation
bin110101100110101011…
…1001000110001110001
3102000010112022202002120
41223031113020301301
53341223310403431
6124514412104453
711213434324104
oct1531527106161
9360115282076
10115114544241
1144902182984
121a387765129
13ab16cc2348
14580058073b
152edb128196
hex1acd5c8c71

115114544241 has 4 divisors (see below), whose sum is σ = 153486058992. Its totient is φ = 76743029492.

The previous prime is 115114544221. The next prime is 115114544257. The reversal of 115114544241 is 142445411511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115114544241 - 27 = 115114544113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115114544201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19185757371 + ... + 19185757376.

It is an arithmetic number, because the mean of its divisors is an integer number (38371514748).

Almost surely, 2115114544241 is an apocalyptic number.

It is an amenable number.

115114544241 is a deficient number, since it is larger than the sum of its proper divisors (38371514751).

115114544241 is an equidigital number, since it uses as much as digits as its factorization.

115114544241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38371514750.

The product of its digits is 12800, while the sum is 33.

Adding to 115114544241 its reverse (142445411511), we get a palindrome (257559955752).

The spelling of 115114544241 in words is "one hundred fifteen billion, one hundred fourteen million, five hundred forty-four thousand, two hundred forty-one".

Divisors: 1 3 38371514747 115114544241