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115116431217 = 338372143739
BaseRepresentation
bin110101100110101111…
…0010101011101110001
3102000010122212121112120
41223031132111131301
53341224301244332
6124514520344453
711213456343354
oct1531536253561
9360118777476
10115116431217
1144903251667
121a388315129
13ab175031b8
14580091229b
152edb39c32c
hex1acd795771

115116431217 has 4 divisors (see below), whose sum is σ = 153488574960. Its totient is φ = 76744287476.

The previous prime is 115116431207. The next prime is 115116431231. The reversal of 115116431217 is 712134611511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115116431217 - 222 = 115112236913 is a prime.

It is a super-2 number, since 2×1151164312172 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (115116431207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19186071867 + ... + 19186071872.

It is an arithmetic number, because the mean of its divisors is an integer number (38372143740).

Almost surely, 2115116431217 is an apocalyptic number.

It is an amenable number.

115116431217 is a deficient number, since it is larger than the sum of its proper divisors (38372143743).

115116431217 is an equidigital number, since it uses as much as digits as its factorization.

115116431217 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38372143742.

The product of its digits is 5040, while the sum is 33.

The spelling of 115116431217 in words is "one hundred fifteen billion, one hundred sixteen million, four hundred thirty-one thousand, two hundred seventeen".

Divisors: 1 3 38372143739 115116431217