Base | Representation |
---|---|
bin | 10101011100010101… |
… | …11111110110100001 |
3 | 1002201021221220010000 |
4 | 22232022333312201 |
5 | 142034041200103 |
6 | 5142155130213 |
7 | 555164560116 |
oct | 125612776641 |
9 | 32637856100 |
10 | 11512053153 |
11 | 4978287a17 |
12 | 2293443969 |
13 | 111603c993 |
14 | 7b2cc290d |
15 | 4759d8aa3 |
hex | 2ae2bfda1 |
11512053153 has 20 divisors (see below), whose sum is σ = 17200846960. Its totient is φ = 7672993272.
The previous prime is 11512053131. The next prime is 11512053167. The reversal of 11512053153 is 35135021511.
11512053153 is a `hidden beast` number, since 1 + 1 + 5 + 120 + 531 + 5 + 3 = 666.
It is not a de Polignac number, because 11512053153 - 213 = 11512044961 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11512053193) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 425826 + ... + 452052.
It is an arithmetic number, because the mean of its divisors is an integer number (860042348).
Almost surely, 211512053153 is an apocalyptic number.
It is an amenable number.
11512053153 is a deficient number, since it is larger than the sum of its proper divisors (5688793807).
11512053153 is an equidigital number, since it uses as much as digits as its factorization.
11512053153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31658 (or 31649 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 11512053153 its reverse (35135021511), we get a palindrome (46647074664).
The spelling of 11512053153 in words is "eleven billion, five hundred twelve million, fifty-three thousand, one hundred fifty-three".
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