11512344163 has 4 divisors (see below), whose sum is σ = 11558210328. Its totient is φ = 11466478000.

The previous prime is 11512344139. The next prime is 11512344187. The reversal of 11512344163 is 36144321511.

11512344163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 36144321511 = 149 ⋅242579339.

It is an interprime number because it is at equal distance from previous prime (11512344139) and next prime (11512344187).

It is a cyclic number.

It is not a de Polignac number, because 11512344163 - 2³³ = 2922409571 is a prime.

It is a super-3 number, since 3×11512344163³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11512344763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22932706 + ... + 22933207.

It is an arithmetic number, because the mean of its divisors is an integer number (2889552582).

Almost surely, 2^11512344163 is an apocalyptic number.

11512344163 is a deficient number, since it is larger than the sum of its proper divisors (45866165).

11512344163 is an equidigital number, since it uses as much as digits as its factorization.

11512344163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45866164.

The product of its digits is 8640, while the sum is 31.

Adding to 11512344163 its reverse (36144321511), we get a palindrome (47656665674).

The spelling of 11512344163 in words is "eleven billion, five hundred twelve million, three hundred forty-four thousand, one hundred sixty-three".