11512344331153 has 8 divisors (see below), whose sum is σ = 11563063649280. Its totient is φ = 11461670937600.

The previous prime is 11512344331123. The next prime is 11512344331157. The reversal of 11512344331153 is 35113344321511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11512344331153 - 2⁵ = 11512344331121 is a prime.

It is a super-3 number, since 3×11512344331153³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11512344331157) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10978633 + ... + 11981446.

It is an arithmetic number, because the mean of its divisors is an integer number (1445382956160).

Almost surely, 2^{11512344331153} is an apocalyptic number.

It is an amenable number.

11512344331153 is a deficient number, since it is larger than the sum of its proper divisors (50719318127).

11512344331153 is a wasteful number, since it uses less digits than its factorization.

11512344331153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22962287.

The product of its digits is 64800, while the sum is 37.

Adding to 11512344331153 its reverse (35113344321511), we get a palindrome (46625688652664).

The spelling of 11512344331153 in words is "eleven trillion, five hundred twelve billion, three hundred forty-four million, three hundred thirty-one thousand, one hundred fifty-three".