11512512660433 has 8 divisors (see below), whose sum is σ = 11912111803136. Its totient is φ = 11114677753200.

The previous prime is 11512512660421. The next prime is 11512512660521. The reversal of 11512512660433 is 33406621521511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11512512660433 is a prime.

It is a super-2 number, since 2×11512512660433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11512512660403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441045591 + ... + 441071692.

It is an arithmetic number, because the mean of its divisors is an integer number (1489013975392).

Almost surely, 2^{11512512660433} is an apocalyptic number.

It is an amenable number.

11512512660433 is a deficient number, since it is larger than the sum of its proper divisors (399599142703).

11512512660433 is an equidigital number, since it uses as much as digits as its factorization.

11512512660433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 882117735.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 11512512660433 in words is "eleven trillion, five hundred twelve billion, five hundred twelve million, six hundred sixty thousand, four hundred thirty-three".