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11513002073 = 23087498679
BaseRepresentation
bin10101011100011101…
…00111100001011001
31002201100202002210012
422232032213201121
5142034312031243
65142231331305
7555205621466
oct125616474131
932640662705
1011513002073
114978875951
122293820b35
1311162b2881
147b308c66d
15475b24d18
hex2ae3a7859

11513002073 has 4 divisors (see below), whose sum is σ = 11513523840. Its totient is φ = 11512480308.

The previous prime is 11513002069. The next prime is 11513002087. The reversal of 11513002073 is 37020031511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11513002073 - 22 = 11513002069 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11513002273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226253 + ... + 272426.

It is an arithmetic number, because the mean of its divisors is an integer number (2878380960).

Almost surely, 211513002073 is an apocalyptic number.

It is an amenable number.

11513002073 is a deficient number, since it is larger than the sum of its proper divisors (521767).

11513002073 is an equidigital number, since it uses as much as digits as its factorization.

11513002073 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 521766.

The product of its (nonzero) digits is 630, while the sum is 23.

Adding to 11513002073 its reverse (37020031511), we get a palindrome (48533033584).

The spelling of 11513002073 in words is "eleven billion, five hundred thirteen million, two thousand, seventy-three".

Divisors: 1 23087 498679 11513002073