115130040403 has 8 divisors (see below), whose sum is σ = 133807311360. Its totient is φ = 97010300040.

The previous prime is 115130040391. The next prime is 115130040407. The reversal of 115130040403 is 304040031511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115130040403 - 2²⁵ = 115096485971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115130040407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 139382203 + ... + 139383028.

It is an arithmetic number, because the mean of its divisors is an integer number (16725913920).

Almost surely, 2^115130040403 is an apocalyptic number.

115130040403 is a deficient number, since it is larger than the sum of its proper divisors (18677270957).

115130040403 is an equidigital number, since it uses as much as digits as its factorization.

115130040403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278765297.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 115130040403 its reverse (304040031511), we get a palindrome (419170071914).

The spelling of 115130040403 in words is "one hundred fifteen billion, one hundred thirty million, forty thousand, four hundred three".