11513144251403 has 4 divisors (see below), whose sum is σ = 11513153339520. Its totient is φ = 11513135163288.

The previous prime is 11513144251397. The next prime is 11513144251451. The reversal of 11513144251403 is 30415244131511.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11513144251403 - 2⁴ = 11513144251387 is a prime.

It is a super-2 number, since 2×11513144251403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11513144259403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2261675 + ... + 5304852.

It is an arithmetic number, because the mean of its divisors is an integer number (2878288334880).

Almost surely, 2^{11513144251403} is an apocalyptic number.

11513144251403 is a deficient number, since it is larger than the sum of its proper divisors (9088117).

11513144251403 is an equidigital number, since it uses as much as digits as its factorization.

11513144251403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9088116.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 11513144251403 its reverse (30415244131511), we get a palindrome (41928388382914).

The spelling of 11513144251403 in words is "eleven trillion, five hundred thirteen billion, one hundred forty-four million, two hundred fifty-one thousand, four hundred three".