Base | Representation |
---|---|
bin | 10101011100011111… |
… | …00010011100010011 |
3 | 1002201101012100211122 |
4 | 22232033202130103 |
5 | 142034342242121 |
6 | 5142240432455 |
7 | 555210645215 |
oct | 125617423423 |
9 | 32641170748 |
10 | 11513243411 |
11 | 4978a201aa |
12 | 229391872b |
13 | 1116368687 |
14 | 7b31125b5 |
15 | 475b715ab |
hex | 2ae3e2713 |
11513243411 has 4 divisors (see below), whose sum is σ = 11532400824. Its totient is φ = 11494086000.
The previous prime is 11513243389. The next prime is 11513243447. The reversal of 11513243411 is 11434231511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11434231511 = 18199 ⋅628289.
It is a cyclic number.
It is not a de Polignac number, because 11513243411 - 218 = 11512981267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11513245411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9577805 + ... + 9579006.
It is an arithmetic number, because the mean of its divisors is an integer number (2883100206).
Almost surely, 211513243411 is an apocalyptic number.
11513243411 is a deficient number, since it is larger than the sum of its proper divisors (19157413).
11513243411 is an equidigital number, since it uses as much as digits as its factorization.
11513243411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19157412.
The product of its digits is 1440, while the sum is 26.
Adding to 11513243411 its reverse (11434231511), we get a palindrome (22947474922).
The spelling of 11513243411 in words is "eleven billion, five hundred thirteen million, two hundred forty-three thousand, four hundred eleven".
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